## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

a) $6 \frac{2}{3}m$ b) $100,000m$ c) $30m/s$ d) $≈ 0.2m$
Using data from the approximation table specified in the question, multiply each of the given units by the ratio between units. a) $20ft \times \frac{1m}{3ft} ≈6 \frac{2}{3}m$ b) $60mi \times \frac{1km}{0.6mi} \times \frac{1000m}{1km} ≈ 100,000m$ c) $60mph \times \frac{1m/s}{2mph} ≈ 30m/s$ d) $8in \times \frac{10cm}{4in} \times \frac{1m}{100cm} ≈ 0.2m$