Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 9 - Impulse and Momentum - Exercises and Problems - Page 241: 31

Answer

$7.5×10^{-10}\;\rm kg.m/s$

Work Step by Step

We know that the impulse is given by $$J=F\Delta t\tag 1$$ We also know that the force exerted on the pollen grains is constant (since the acceleration is constant) and is the only force exerted on them. So that, $$F=ma$$ Plugging into (1); $$J=ma\Delta t $$ Plugging the known; $$J=(1\times10^{-7}\times10^{-3})(2.5\times10^4)(0.3\times10^{-3})$$ $$J=\color{red}{\bf 7.5×10^{-10}}\;\rm kg.m/s$$
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