## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Since the impulse is equal to the area under the graph, the force exerts an impulse of $4~N~s$ on the particle.
The impulse is equal to the area under the force versus time graph. We can find the area under the graph. $Area = (1000~N)(2\times 10^{-3}~s)+\frac{1}{2}(1000~N)(4\times 10^{-3}~s)$ $Area = 4~N~s$ Since the impulse is equal to the area under the graph, the force exerts an impulse of $4~N~s$ on the particle.