Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 8 - Dynamics II: Motion in a Plane - Exercises and Problems - Page 211: 6


(a) $v = 3.93~m/s$ (b) The tension in the string is 6.2 N

Work Step by Step

(a) We can find the speed of the block. $v = (75~rpm)(2\pi ~r)(\frac{1~min}{60~s})$ $v = (75~rpm)(2\pi)(0.50~m)(\frac{1~min}{60~s})$ $v = 3.93~m/s$ (b) The centripetal force is the net force which keeps an object moving in a circle. In this case, the tension provides the centripetal force. $T = \frac{mv^2}{r}$ $T = \frac{(0.200~kg)(3.93~m/s)^2}{0.50~m}$ $T = 6.2~N$ The tension in the string is 6.2 N
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