#### Answer

(a) $v = \sqrt{2\alpha \Delta \theta}~R$
(b) $a_c = (2\alpha \Delta \theta) ~R$

#### Work Step by Step

(a) We can find the angular velocity after the wheel rotates through an angle of $\Delta \theta$:
$\omega^2 = \omega_0^2+2\alpha \Delta \theta$
$\omega^2 = 0+2\alpha \Delta \theta$
$\omega = \sqrt{2\alpha \Delta \theta}$
We can find the velocity.
$v = \omega ~R = \sqrt{2\alpha \Delta \theta}~R$
(b) We can find the centripetal acceleration:
$a_c = \omega^2 ~R$
$a_c = (\sqrt{2\alpha \Delta \theta})^2 ~R$
$a_c = (2\alpha \Delta \theta) ~R$