## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

(a) $v = 30~km/s$ (b) $\omega = 2.0\times 10^{-7}~rad/s$ (c) $a_c = 6.0\times 10^{-3}~m/s^2$
(a) We can find the speed of the earth as: $v = \frac{d}{t}$ $v = \frac{2\pi~r}{t}$ $v = \frac{(2\pi)(1.5\times 10^{11}~m)}{(365)(24)(3600)~s}$ $v = 30000~m/s = 30~km/s$ (b) $\omega = \frac{v}{r}$ $\omega = \frac{30000~m/s}{1.5\times 10^{11}~m}$ $\omega = 2.0\times 10^{-7}~rad/s$ (c) $a_c = \frac{v^2}{r}$ $a_c = \frac{(3.0\times 10^4~m/s)^2}{1.5\times 10^{11}~m}$ $a_c = 6.0\times 10^{-3}~m/s^2$