Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

Chapter 4 - Kinematics in Two Dimensions - Exercises and Problems - Page 111: 14

Answer

The plane should drop the package 678 meters short of the target.

Work Step by Step

We can find the time for the package to drop 100 meters as: $y = \frac{1}{2}gt^2$ $t = \sqrt{\frac{2y}{g}}$ $t = \sqrt{\frac{(2)(100~m)}{9.80~m/s^2}}$ $t = 4.52~s$ The we can find the horizontal distance that the package will travel in 4.52 seconds: $x = v_x~t = (150~m/s)(4.52~s)$ $x = 678~m$ The plane should drop the package 678 meters short of the target.

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