## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can find the slope of the hill; $tan(\theta) = \frac{3}{100}$ $\theta = arctan(\frac{3}{100})$ $\theta = 1.72^{\circ}$ We then find the component of the plane's velocity that is perpendicular to the ground: $v_{perp} = v~sin(\theta)$ $v_{perp} = (500~m/s)~sin(1.72^{\circ})$ $v_{perp} = 15~m/s$ The component of the plane's velocity that is perpendicular to the ground is 15 m/s.