Answer
\begin{array}{|c|c|c|c|}
\hline
{\bf Finally:} & \Delta V\;({\rm V})& Q\;({\rm \mu C})&C\;({\rm \mu F})\\
\hline
\rm Capacitor \;1& 55.5& 833&15\\
\hline
\rm Capacitor \;2& 33.35& 667&20\\
\hline
\rm Capacitor \;3& 22.23&667&30\\
\hline
\end{array}
Work Step by Step
${\bf Initially:}$ We have only one capacitor that is connected to the battery.
So that
$$\Delta V_1=V_B=\color{red}{\bf 100}\;\rm V$$
Hence, the charge stored on this capacitor is given by
$$\Delta V_1=\dfrac{Q_1}{C_1}$$
Thus,
$$Q_1=C_1\Delta V_1$$
$$Q_1=(15\times 10^{-6})(100)=\color{red}{\bf 1500}\;\rm \mu C$$
${\bf Finally:}$ We have 3 capacitors, and the battery is not connected, as we see in the second figure below.
This means that the charge in the $C_1$ will be distributed among the system.
Let's find the equivalent of the two in-series capacitor.
$$(C_{eq})_{23}=\left[ \dfrac{1}{C_2}+\dfrac{1}{C_3}\right]^{-1}$$
Plug the known;
$$(C_{eq})_{23}=\left[ \dfrac{1}{20}+\dfrac{1}{30}\right]^{-1}=\bf 12\;\rm \mu F$$
$$ \Delta V_2C_2=\Delta V_3C_3\tag 1$$
where
$$\Delta V_1= \Delta V_{(C_{eq})_{23}}$$
Hence,
$$\dfrac{Q_1'}{C_1}= \dfrac{Q_{(C_{eq})_{23}}}{(C_{eq})_{23}}$$
$$\dfrac{Q_1'}{15}= \dfrac{Q_{(C_{eq})_{23}}}{12}$$
$$12Q_1' = 15Q_{(C_{eq})_{23}} $$
Therefore,
$$Q_{(C_{eq})_{23}} = \dfrac{4}{5}Q_1'\tag 2$$
Note that the charge $Q_1$ is now divided to the charge $Q_1'$ in the $C_1$ plus the charge $Q_{eq}$ in the $(C_{eq})_{23}$.
Hence,
$$Q_1'+Q_{(C_{eq})_{23}}=1500$$
Plug from (2),
$$Q_1'+ \dfrac{4}{5} Q_1'=1500$$
Hence,
$$Q_1'=\dfrac{5}{9}(1500)=\color{red}{\bf 833}\;\rm\mu C$$
So that,
$$Q_{(C_{eq})_{23}}=1500-833=\bf 667\;\rm \mu C$$
And since the two capacitors are in-series, $Q_2=Q_3$.
Thus,
$$Q_2=Q_3=Q_{(C_{eq})_{23}}=\color{red}{\bf 667}\;\rm \mu C$$
$$\Delta V_1=\dfrac{Q_1'}{C_1}=\dfrac{833}{15}=\color{red}{\bf 55.5}\;\rm V$$
$$\Delta V_2=\dfrac{Q_2 }{C_2}=\dfrac{667}{20}=\color{red}{\bf 33.35}\;\rm V$$
$$\Delta V_3=\dfrac{Q_3}{C_3}=\dfrac{667}{30}=\color{red}{\bf 22.23}\;\rm V$$
\begin{array}{|c|c|c|c|}
\hline
{\bf Finally:} & \Delta V\;({\rm V})& Q\;({\rm \mu C})&C\;({\rm \mu F})\\
\hline
\rm Capacitor \;1& 55.5& 833&15\\
\hline
\rm Capacitor \;2& 33.35& 667&20\\
\hline
\rm Capacitor \;3& 22.23&667&30\\
\hline
\end{array}