Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 28 - The Electric Potential - Conceptual Questions - Page 832: 8

Answer

$$V_{a}= V_{b } \gt V_c\gt V_{e }= V_{f }$$

Work Step by Step

We know that the electric potential at a point that is between two parallel plates of a capacitor is given by $$V=Es$$ where $s$ is measured from the negative plate. Hence, the rank of the electric potentials of the given points are: $$V_{a}= V_{b } $$ $$V_c$$ $$V_{e }= V_{f } $$ Therefore, $$\boxed{V_{a}= V_{b } \gt V_c\gt V_{e }= V_{f } }$$
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