Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 27 - Gauss's Law - Conceptual Questions - Page 804: 8


Student 1 is correct .

Work Step by Step

As the electric flux passing through a surface depends on the charge enclosed by the surface. That is, $\phi=E.dA$, where $E$ is electric field and $dA$ is surface area. So, flux depends on both electric field and surface area. In case of surface A its surface area is small but its electric field is large while in case of B its surface area is large but its electric field is small. Thus, $\phi=\frac{q}{\epsilon_{0}}$ and the charge is same for both surface A and surface B, therefore, the flux passing through them will also be same. Hence, Student 1 is correct.
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