Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 25 - Electric Charges and Forces - Exercises and Problems - Page 745: 5


$q = 1.93\times 10^5~C$

Work Step by Step

There are 2 protons in each atom of helium. Each proton has a charge of $1.6\times 10^{-19}~C$. We can find the total charge of all the protons. $q = (1~mol)(2)(1.6\times 10^{-19}~C)$ $q = (6.02\times 10^{23})(2)(1.6\times 10^{-19}~C)$ $q = 1.93\times 10^5~C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.