Answer
$q = 1.93\times 10^5~C$
Work Step by Step
There are 2 protons in each atom of helium. Each proton has a charge of $1.6\times 10^{-19}~C$. We can find the total charge of all the protons.
$q = (1~mol)(2)(1.6\times 10^{-19}~C)$
$q = (6.02\times 10^{23})(2)(1.6\times 10^{-19}~C)$
$q = 1.93\times 10^5~C$