Answer
$D = 0.50~m$
Work Step by Step
We can find the required diameter of the aperture:
$w = \frac{2.44~\lambda~L}{D}$
$D = \frac{2.44~\lambda~L}{w}$
$D = \frac{(2.44)(532\times 10^{-9}~m)(3.84\times 10^{8}~m)}{10^3~m}$
$D = 0.50~m$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.