Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 649: 24

Answer

$L = 0.78~m$

Work Step by Step

We can find the required distance $L$: $w = \frac{2.44~\lambda~L}{d}$ $L = \frac{w~d}{2.44~\lambda}$ $L = \frac{(0.010~m)(0.12\times 10^{-3}~m)}{(2.44)~(633\times 10^{-9}~m)}$ $L = 0.78~m$
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