## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$f = 15.9~Hz$ $A = 2.0~cm$
We write an expression for the maximum speed. $v_{max} = A~\omega$ We write an expression for the maximum acceleration. $a_{max} = A~\omega^2$ We divide the second equation by the first equation. $\frac{a_{max}}{v_{max}} = \frac{A~\omega^2}{A~\omega}$ $\omega = \frac{a_{max}}{v_{max}}$ $\omega = \frac{200~m/s^2}{2.0~m/s}$ $\omega = 100~rad/s$ We find the frequency. $f = \frac{\omega}{2\pi}$ $f = \frac{100~rad/s}{2\pi}$ $f = 15.9~Hz$ We find the amplitude. $v_{max} = A~\omega$ $A = \frac{v_{max}}{\omega}$ $A = \frac{2.0~m/s}{100~rad/s}$ $A = 0.020~m = 2.0~cm$