Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 20 - Traveling Waves - Exercises and Problems - Page 588: 48

Answer

The wavelength of the laser beam in the liquid is 459 nm

Work Step by Step

We can find the speed in the liquid as: $v = \frac{d}{t}$ $v = \frac{0.30~m}{1.38\times 10^{-9}~s}$ $v = 2.174\times 10^8~m/s$ We can find the index of refraction of the liquid as: $v = \frac{c}{n}$ $n = \frac{c}{v}$ $n = \frac{3.0\times 10^8~m/s}{2.174\times 10^8~m/s}$ $n = 1.38$ We can find the wavelength in the liquid as: $n = \frac{\lambda_a}{\lambda_l}$ $\lambda_l = \frac{\lambda_a}{n}$ $\lambda_l = \frac{633~nm}{1.38}$ $\lambda_l = 459~nm$ The wavelength of the laser beam in the liquid is 459 nm.
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