Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 20 - Traveling Waves - Conceptual Questions - Page 585: 10

Answer

$P_B = P_C \gt P_A$

Work Step by Step

We can find $P_A$: $P_A = \frac{E_A}{t_A}$ $P_A = \frac{2~J}{2~s}$ $P_A = 1~J/s$ $P_A = 1~W$ We can find $P_B$: $P_B = \frac{E_B}{t_B}$ $P_B = \frac{10~J}{5~s}$ $P_B = 2~J/s$ $P_B = 2~W$ We can find $P_C$: $P_C = \frac{E_C}{t_C}$ $P_C = \frac{2\times 10^{-3}~J}{1\times 10^{-3}~s}$ $P_C = 2~J/s$ $P_C = 2~W$ We can rank the power of the sound waves in order from largest to smallest. $P_B = P_C \gt P_A$
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