## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$P_B = P_C \gt P_A$
We can find $P_A$: $P_A = \frac{E_A}{t_A}$ $P_A = \frac{2~J}{2~s}$ $P_A = 1~J/s$ $P_A = 1~W$ We can find $P_B$: $P_B = \frac{E_B}{t_B}$ $P_B = \frac{10~J}{5~s}$ $P_B = 2~J/s$ $P_B = 2~W$ We can find $P_C$: $P_C = \frac{E_C}{t_C}$ $P_C = \frac{2\times 10^{-3}~J}{1\times 10^{-3}~s}$ $P_C = 2~J/s$ $P_C = 2~W$ We can rank the power of the sound waves in order from largest to smallest. $P_B = P_C \gt P_A$