Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can find the acceleration of the puck. $a = \frac{v^2-v_0^2}{2d}$ $a = \frac{(4.0~m/s)^2-(5.0~m/s)^2}{(2)(3.0~m)}$ $a = -1.5~m/s^2$ We can find the distance the puck moves with an initial speed of 5.0 m/s $d = \frac{v^2-v_0^2}{2a}$ $d = \frac{0-(5.0~m/s)^2}{(2)(-1.5~m/s^2)}$ $d = 8.33~m$ The puck was initially 8.5 meters from the end of the ramp. The puck reaches a distance of 0.17 m from the end of the ramp. Since the puck needed to come within 10 cm of the end of the ramp, the person is not a winner.