Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 65: 41

Answer

a)$a = 2.68 m/s^2$ b) $ a= \frac{67}{245}g$ c) $134.1 m \\ 440 feet$

Work Step by Step

$1 mile =1.609km =1609m$ $1mile = 5280 feet$ $v_i =0 , v_f=60mph =\frac{60}{3600}miles/s = \frac{1}{60}miles/s$ $ t=10 s$ $ a=\frac{ v_f -v_i}{t} = \frac{1}{600} miles/s^2$ a) $a=\frac{1}{600} * 1609 m/s^2$ $a = 2.68 m/s^2$ b) $ \frac{a}{g} =\frac{2.68}{9.8} = \frac{67}{245}$ $\implies a= \frac{67}{245}g$ c) we have $ s = ut +\frac{1}{2}at^2$ $s = 0 +\frac{1}{2}(\frac{1}{600}(10)^2 miles$ $s = \frac{1}{12}miles$ $s = \frac{1}{12} * 1609 m= 134.1 m$ $s =\frac{1}{12}* 5280 feet = 440 feet$
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