## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

(a) Yes, the particle has a turning point at t = 1 s. Note that at t = 1 s, the velocity is zero as it changes from a negative velocity to a positive velocity. (b) The area between the velocity versus time graph and the x-axis is equal to the displacement. From t = 0 to t = 2 s: $\Delta x=0$ At t = 2 s: $x=x_0+\Delta x$ $x=10 ~m+0$ $x=10 ~m$ From t = 2 to t = 3 s: $\Delta x=6 ~m$ At t = 3 s: $x=10 ~m+6 ~m$ $x=16 ~m$ From t = 3 to t = 4 s: $\Delta x=10 ~m$ At t = 4 s: $x=16 ~m+10 ~m$ $x=26 ~m$