Answer
$490J$
Work Step by Step
The required thermal energy of the gas can be determined as follows:
$K.E_{avg}=\frac{1}{2}mv^2$
We plug in the known values to obtain:
$K.E_{avg}=\frac{1}{2}(2\times 10^{-3})(700)^2$
This simplifies to:
$K.E_{avg}=490J$
