Answer
a) $Q_1 =250J$
b)$Q_2 = 150J$
Work Step by Step
a)We have
$ \eta = \frac{W}{Q_1}$
$ 40\% = \frac{100J}{Q_1}$
$ Q_1 = 100J *\frac{100}{40}$
$Q_1 =250J$
b) Also $ W=Q_1 -Q_2$
$ 100J = 250J -Q_2$
$Q_2 = 150J$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 18 - Heat Engines and Refrigerators - Exercises and Problems - Page 549: 1
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