Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 15 - Fluids and Elasticity - Exercises and Problems - Page 437: 37


The total mass of the atmosphere is $5.29\times 10^{18}~kg$

Work Step by Step

The atmospheric pressure comes from the weight of the atmosphere pushing down on the earth's surface area. Let $M$ be the mass of the atmosphere. $\frac{F}{A} = P$ $Mg = P~A$ $M = \frac{P~A}{g}$ $M = \frac{P~(4\pi~R^2)}{g}$ $M = \frac{(1.013\times 10^5~N/m^2)~(4\pi)(6.38\times 10^6~m)^2}{9.80~m/s^2}$ $M = 5.29\times 10^{18}~kg$ The total mass of the atmosphere is $5.29\times 10^{18}~kg$.
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