## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

A liquid with a density of $1260~kg/m^3$ is Glycerin, so we can conclude that Glycerin is the liquid in container B.
The containers have equal volumes. Since the mass of the liquid is 7060 times the mass of the helium, the density of the liquid must be 7060 times the density of the helium. $\rho_L = (7060)~\rho_{He}$ $\rho_L = (7060)(0.179~kg/m^3)$ $\rho_L = 1260~kg/m^3$ A liquid with a density of $1260~kg/m^3$ is Glycerin, so we can conclude that Glycerin is the liquid in container B.