# Chapter 14 - Oscillations - Exercises and Problems: 25

$k = 0.079~N/m$

#### Work Step by Step

We can assume that the period is 1.0 s. We can find the spring constant of the silk thread as: $T = 2\pi~\sqrt{\frac{m}{k}}$ $k = \frac{(2\pi)^2~m}{T^2}$ $k = \frac{(2\pi)^2~(0.0020~kg)}{(1.0~s)^2}$ $k = 0.079~N/m$

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