Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 14 - Oscillations - Conceptual Questions - Page 401: 3


$f = 0.5~Hz$ $A = 10~cm$

Work Step by Step

From the graph, we can see that one cycle is completed every 2 seconds. Therefore, the period $T = 2~s$. $f = \frac{1}{T} = \frac{1}{2~s} = 0.5~Hz$ The motion moves between -10 cm and 10 cm. Therefore, the oscillation amplitude is 10 cm.
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