Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 14 - Oscillations - Conceptual Questions: 3

Answer

$f = 0.5~Hz$ $A = 10~cm$

Work Step by Step

From the graph, we can see that one cycle is completed every 2 seconds. Therefore, the period $T = 2~s$. $f = \frac{1}{T} = \frac{1}{2~s} = 0.5~Hz$ The motion moves between -10 cm and 10 cm. Therefore, the oscillation amplitude is 10 cm.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.