## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$v = 13.2~m/s$
We can find the angular velocity of the skater as: $\omega = (180~rpm)(\frac{1~min}{60~s})(\frac{2\pi~rad}{1~rev})$ $\omega = 6\pi~rad/s$ We then find the speed of the hands. Note that the radius of rotation of the hands is 0.70 meters. $v = \omega ~r$ $v = (6\pi~rad/s)(0.70~m)$ $v = 13.2~m/s$