Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We first find the kinetic energy of the bullet; $KE = \frac{1}{2}mv^2$ $KE = \frac{1}{2}(0.010~kg)(500~m/s)^2$ $KE = 1250~joules$ We then find the kinetic energy of the bowling ball; $KE = \frac{1}{2}mv^2$ $KE = \frac{1}{2}(10~kg)(10~m/s)^2$ $KE = 500~joules$ The bullet has the larger kinetic energy.