Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 10 - Energy - Conceptual Questions: 3

Answer

The particle's kinetic energy increases by a factor of 9

Work Step by Step

We can write an expression for the kinetic energy when the speed is $v$: $KE_1 = \frac{1}{2}mv^2$ We can write an expression for the kinetic energy when the speed is $3v$: $KE_2 = \frac{1}{2}m(3v)^2$ $KE_2 = 9\times ~\frac{1}{2}mv^2$ $KE_2 = 9\times ~KE_1$ The particle's kinetic energy increases by a factor of 9.
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