## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 1 - Concepts of Motion - Exercises and Problems - Page 32: 54

#### Answer

a. 2.7 $\times$ $10^{3}$ kg/m³ b. 8.1 $\times$ $10^{2}$ kg/m³

#### Work Step by Step

1 cm³ = $10^{-6}$ m³ and 1 g = $10^{-3}$ kg a. 2.7 $\times$ $10^{-3}$ kg/cm³ = 2.7 $\times$ $10^{-3}$ kg/($10^{-6}$ m³) = 2.7 $\times$ $10^{-3}$ $\times$ $10^{6}$ kg/ m³ = 2.7 $\times$ $10^{3}$ kg/m³ b. 0.81 g/cm³ = 0.81 $\times$ $10^{-3}$ kg/($10^{-6}$ m³) = 0.81 $\times$ $10^{-3}$ $\times$ $10^{6}$ kg/m³ = 8.1 $\times$ $10^{2}$ kg/m³

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