Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 9 - Rotational Dynamics - Problems - Page 244: 11

Answer

The center of gravity for his entire body is located $1.03m$ above the floor.

Work Step by Step

The center of gravity is calculated by $$x_{cg}=\frac{W_1x_1+W_2x_2+W_3x_3}{W_1+W_2+W_3}$$ The total weight of head, upper torso, arms and hands is $W_1=438N$ and its center of gravity $x_1=1.28m$ The total weight of the upper legs is $W_2=144N$, and the center of gravity $x_2=0.76m$ The total weight of lower legs and feet is $W_3=87N$, and its center of gravity is $x_3=0.25m$ Therefore, $$x_{cg}=1.03m$$
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