Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 9 - Rotational Dynamics - Problems - Page 243: 3

Answer

$F=210N$

Work Step by Step

The figure below shows that we can turn the distance $0.28m$ into the lever arm by finding the angle to the left of $F$ and change $F$ into a force component $F\cos40$ In other words, the torque produced by force $F$ equals $$\tau=(F\cos40)l$$ $$F=\frac{\tau}{l\cos40}=\frac{45}{0.28\times\cos40}=210N$$
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