## Physics (10th Edition)

The radius of the blade is $0.3m$
We have $$v_T=r\omega$$ $$r=\frac{v_T}{\omega}$$ It is given $v_T=32m/s$ and $\omega=17rev/s\times\Big(\frac{2\pi rad}{1rev}\Big)=106.8rad/s$ Therefore, $$r=0.3m$$