Answer
The radius of the blade is $0.3m$
Work Step by Step
We have $$v_T=r\omega$$ $$r=\frac{v_T}{\omega}$$
It is given $v_T=32m/s$ and $\omega=17rev/s\times\Big(\frac{2\pi rad}{1rev}\Big)=106.8rad/s$
Therefore, $$r=0.3m$$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 8 - Rotational Kinematics - Check Your Understanding - Page 206: 11
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