Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 7 - Impulse and Momentum - Problems - Page 195: 58

Answer

The recoil velocity is $-1.47\times10^{-4}m/s$

Work Step by Step

The patient and platform has mass $M=85kg$ and initial velocity $V_0=0$. The blood has mass $m=0.05kg$, and its initial velocity can be considered to be $v_0=0$. After the heartbeat, $v_f=+0.25m/s$ Since total momentum is conserved, we can the find the recoil velocity of the patient and the platform $V_f$: $$MV_0+mv_0=MV_f+mv_f=0$$ $$85V_f+0.0125=0$$ $$V_f=-1.47\times10^{-4}m/s$$
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