Answer
The speed the rocket will achieve is $165.7m/s$
Work Step by Step
The impulse-momentum theorem states that $$J=mv_f-mv_0$$ $$v_f=\frac{J+mv_0}{m}$$
We have $J=29N.s$, $m=0.175kg$ and $v_0=0$
The speed the rocket will achieve is $$v_f=165.7m/s$$
