Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 7 - Impulse and Momentum - Focus On Concepts - Page 190: 2

Answer

d) is correct.

Work Step by Step

We have $p_A=\frac{1}{2}m_0v_0$; its vector is directed due north. $p_B=m_0v_0$; its vector is directed due east. $p_C=2m_0v_0$; its vector is directed due south. $p_D=2m_0v_0$; its vector is directed due west. $p_E=\frac{1}{2}m_0v_0$; its vector is directed due north. $p_F=4m_0v_0$; its vector is directed due west. So runners A and E have identical momenta.
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