Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 171: 88


$\overline P=5.82\times10^4W$

Work Step by Step

According to Newton's 2nd law of motion, $$F=ma$$ We have $m=1.1\times10^3kg$ and $a=4.6m/s^2$, so $$F=5.06\times10^3N$$ The distance the vehicle has gone in $5s$: $$s=v_0t+\frac{1}{2}at^2=0+\frac{1}{2}\times4.6\times5^2=57.5m$$ The work done on the car is $$W=(F\cos\theta)s=Fs=2.91\times10^5J$$ ($\cos\theta=\cos0=1$ because $F$ is horizontal like the car's displacement.) The average power generated by $F$ over $5s$ is $$\overline P=\frac{W}{t}=5.82\times10^4W$$
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