Answer
b) is correct.
Work Step by Step
According to the work-energy theorem, $$\sum W=W_1+W_2=\frac{1}{2}m(v_f^2-v_0^2)$$
Since $v_f= v_0$, it means $$\sum W=W_1+W_2=0$$ $$W_1=-W_2$$
b) is correct.
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 6 - Work and Energy - Focus On Concepts - Page 165: 9
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