Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 137: 2


Example 1: $a=288m/s^2$ Example 2: $a=0$ Example 3: $a=2.94m/s^2$

Work Step by Step

The magnitude of the centripetal acceleration can be calculated with the following formula: $$a=\frac{v^2}{r}$$ (a) Example 1: speed $v=12m/s$, radius $r=0.5m$ $$a=\frac{12^2}{0.5}=288m/s^2$$ (a) Example 2: speed $v=35m/s$, radius $r$ infinitely large $$a=\frac{v^2}{r}=0$$ (a) Example 1: speed $v=2.3m/s$, radius $r=1.8m$ $$a=\frac{2.3^2}{1.8}=2.94m/s^2$$
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