Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Focus On Concepts - Page 137: 8


(a) is the correct answer.

Work Step by Step

We take $$F=\frac{m_0v_0^2}{r_0}$$ - Particle 1: $$F_c=\frac{m_0(2v_0)^2}{r_0}=\frac{4m_0v_0^2}{r_0}=4F$$ - Particle 2: $$F_c=\frac{m_0(3v_0)^2}{3r_0}=\frac{9m_0v_0^2}{3r_0}=\frac{3m_0v_0^2}{r_0}=3F$$ - Particle 3: $$F_c=\frac{2m_0(2v_0)^2}{4r_0}=\frac{8m_0v_0^2}{4r_0}=\frac{2m_0v_0^2}{r_0}=2F$$ To rank from largest to smallest: (a) 1, 2, 3.
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