Answer
(a) is the correct answer.
Work Step by Step
We take $$F=\frac{m_0v_0^2}{r_0}$$
- Particle 1: $$F_c=\frac{m_0(2v_0)^2}{r_0}=\frac{4m_0v_0^2}{r_0}=4F$$
- Particle 2: $$F_c=\frac{m_0(3v_0)^2}{3r_0}=\frac{9m_0v_0^2}{3r_0}=\frac{3m_0v_0^2}{r_0}=3F$$
- Particle 3: $$F_c=\frac{2m_0(2v_0)^2}{4r_0}=\frac{8m_0v_0^2}{4r_0}=\frac{2m_0v_0^2}{r_0}=2F$$
To rank from largest to smallest: (a) 1, 2, 3.
