Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 31 - Nuclear Physics and Radioactivity - Problems - Page 901: 34



Work Step by Step

$T_{\frac{1}{2}}=14.28\,day= 14.28\,day\times\frac{(60\times60\times24)s}{1\,day}$$=1.234\times10^{6}\,s$ Thus, we find: Decay constant $\lambda= \frac{0.693}{T_{\frac{1}{2}}}=\frac{0.693}{1.234\times10^{6}s}= 5.62\times10^{-7}s^{-1}$
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