## Physics (10th Edition)

Given: Image distance v= -26 cm Focal length f= -12 cm According to the mirror equation: Object distance $u= \frac{vf}{v-f}$. Thus, we find: $u=\frac{-26\times-12}{-26-(-12)}cm\approx -22 cm$. The object is located at a distance of 22 cm in front of the mirror.