Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 22 - Electromagnetic Induction - Problems - Page 645: 15


$2.2\times10^{-3}$ Wb

Work Step by Step

$B= 0.078 T$ $A= \pi r^{2}=\pi(0.10 m)^{2}$ $\theta= 25^{\circ}$ Thus, we find: $\phi_{B}=BA\cos \theta$$=0.078 T\times\pi(0.10 m)^{2}\times\cos 25^{\circ}=0.0022$ Wb
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