Answer
$2.2\times10^{-3}$ Wb
Work Step by Step
$B= 0.078 T$
$A= \pi r^{2}=\pi(0.10 m)^{2}$
$\theta= 25^{\circ}$
Thus, we find:
$\phi_{B}=BA\cos \theta$$=0.078 T\times\pi(0.10 m)^{2}\times\cos 25^{\circ}=0.0022$ Wb
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.