## Physics (10th Edition)

$1.3\times10^{6}\,J$
$I=\frac{q}{t} \implies q=It=6.0\,A\times5.0\,h\times\frac{3600\,s}{1\,h}=1.08\times10^{5}\,C$ Now, $Energy=\frac{Energy}{Charge}\times Charge$ $\frac{Energy}{Charge}=Battery\,voltage=12\,V$ We found charge q to be equal to $1.08\times10^{5}\,C$ Therefore energy delivered to the battery $U=12\,V\times1.08\times10^{5}\,C=1.3\times10^{6}\,J$