Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Problems - Page 572: 3



Work Step by Step

$I=\frac{q}{t} \implies q=It=6.0\,A\times5.0\,h\times\frac{3600\,s}{1\,h}=1.08\times10^{5}\,C$ Now, $Energy=\frac{Energy}{Charge}\times Charge$ $\frac{Energy}{Charge}=Battery\,voltage=12\,V$ We found charge q to be equal to $1.08\times10^{5}\,C$ Therefore energy delivered to the battery $U=12\,V\times1.08\times10^{5}\,C=1.3\times10^{6}\,J$
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