Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 20 - Electric Circuits - Focus On Concepts - Page 571: 5

Answer

(a)A,B,C

Work Step by Step

we have $P=VI$ Doubling the voltage and reducing the current by a factor of two $ P' = 2V* \frac{1}{2}I =P$ Also $P = \frac{V^2}{R}$ Doubling the voltage and increasing the resistance by a factor of four $ P' = \frac{(2V)^2} {4R} = \frac {V^2}{R} =P$ Also $ P = I^2R$ Doubling the current and reducing the resistance by a factor of four $ P' = (2I)^2 (\frac{1}{4}R) = I^2R =P$
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