Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 47: 6


a) 7.07 km b) 2.12 km NE

Work Step by Step

a) distance = $\frac{3}{4}$ $\times$ 2$\pi$r = $\frac{3}{4}$ $\times$ 2$\pi$(1.50) $\approx$ 7.07 km b) displacement = $\sqrt (1.50^{2}+1.50^{2}$) $\approx$ 2.12 km NE
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