## Physics (10th Edition)

a) distance = $\frac{3}{4}$ $\times$ 2$\pi$r = $\frac{3}{4}$ $\times$ 2$\pi$(1.50) $\approx$ 7.07 km b) displacement = $\sqrt (1.50^{2}+1.50^{2}$) $\approx$ 2.12 km NE