## Physics (10th Edition)

$\sqrt 6$ $v$
$v^{2}=u^{2}+2ax$ sub $u=0$ $v^{2}=2ax$ $v=\sqrt (2ax)$ $v_{new}$ =$\sqrt (2a(3x))$ =$\sqrt (6ax)$ = $\sqrt 6\times\sqrt (2ax)$ =$\sqrt 6\times\ v$