Answer
Net charge $=+2.56\times10^{-18}C$
Work Step by Step
Electric charge on $1$ proton $q_{p}=+e=+1.6\times10^{-19}C$
Electrical charge on $1$ electron $q_{e}= -e=-1.6\times10^{-19}C$
Given the Iron atom is with $26$ $ proton$ and $7$ $ electron$
Net charge $= 26\times q_{p} +7\times q_{e}$
Net charge$ =26\times 1.6\times10^{-19}C +7\times (-1.6\times10^{-19})C$
Net charge $=+1.6\times10^{-19}C(26-7)$
Net charge $=+1.6\times10^{-19}C\times16$
Net charge $=+25.6\times10^{-19}C$
Net charge $=+2.56\times10^{-18}C$
