Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 18 - Electric Forces and Electric Fields - Check Your Understanding - Page 496: 11

Answer

The positive and negative charge experience forces that differ both in magnitude as well as direction. Correct statement therefore is option (d)

Work Step by Step

Say the positive charge has magnitude $p$ and the negative charge has magnitude $n$. Given $p\ne n$ Force due to electric field $\vec{E}$ on charge $q$ is given by $$\vec{F} = q\vec{E}$$ For the positive charge: $$\vec{F_p} = p\vec{E}$$ For the negative charge: $$\vec{F_n} = -n\vec{E}$$ Clearly $\vec{F_p}\ne\vec{F_n}$ both in magnitude as well as direction.
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