Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 14 - The Ideal Gas Law and Kinetic Theory - Problems - Page 384: 19

Answer

$2.2\space kg/m^{3}$

Work Step by Step

We can write, $Density\space (\rho)=\frac{mass(m)}{volume(V)}=\frac{n(Mass\space per\space mole)}{V}-(1)$ Let's apply the ideal gas law $PV=nRT$ to the substance. $PV=nRT=> n=\frac{PV}{RT}-(2)$ (2)=>(1), $\rho=\frac{(\frac{PV}{RT})(mass\space per\space mole)}{V}=\frac{P(mass\space per\space mole)}{RT}$ Let's plug known values into this equation. $\rho=\frac{2(1.013\times10^{5}Pa)(28\times10^{-3}g/mol)}{(8.31\space J/mol\space K)(310\space K)}=2.2\space kg/m^{3}$ Density of the substance = $2.2\space kg/m^{3}$
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